SSC CGL Quant – Simplification & Approximation – Tier II Level · Marathon

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SSC CGL Quant – Simplification & Approximation – Tier II Level · Marathon – 10 questions, subject: Quantitative Aptitude. Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.

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1.  
1/(√1 + √2) + 1/(√2 + √3) + … + 1/(√24 + √25) = ?

Correct Answer: B [4]

Explanation:

Each term is √(n + 1) − √n; sum = √25 − √1 = 4.

2.  
If x = √6 + √5, then x² + 1/x² = ?

Correct Answer: B [22]

Explanation:

1/x = √6 − √5 (since 6 − 5 = 1); (√6 + √5)² + (√6 − √5)² = 2(6 + 5) = 22.

3.  
3.25 expressed as a fraction is:

Correct Answer: D [293/90]

Explanation:

3 + (25 − 2)/90 = 3 + 23/90 = 293/90.

4.  
(8.01)³ − (5.99)² is approximately equal to:

Correct Answer: C [476]

Explanation:

≈ 8³ − 6² = 512 − 36 = 476 (exact ≈ 478.0).

5.  
(√7 + √3)/(√7 − √3) + (√7 − √3)/(√7 + √3) = ?

Correct Answer: A [5]

Explanation:

[(√7 + √3)² + (√7 − √3)²]/(7 − 3) = 2 × 10/4 = 5.

6.  
1/(1 × 4) + 1/(4 × 7) + 1/(7 × 10) + … + 1/(28 × 31) = ?

Correct Answer: C [10/31]

Explanation:

Gap 3: (1/3)(1 − 1/31) = (1/3)(30/31) = 10/31.

7.  
∛0.000729 = ?

Correct Answer: D [0.09]

Explanation:

729 × 10⁻⁶ → 9 × 10⁻² = 0.09.

8.  
If 1/2.56 = 0.390625, then 1/0.000256 = ?

Correct Answer: A [3,906.25]

Explanation:

0.000256 = 2.56 ÷ 10⁴, so its reciprocal is 0.390625 × 10⁴ = 3,906.25.

9.  
[2⅓ of (3/4 ÷ 1/2)] − 1/2 = ?

Correct Answer: B [3]

Explanation:

3/4 ÷ 1/2 = 3/2; 7/3 × 3/2 = 7/2; 7/2 − 1/2 = 3.

10.  
(2.005)² − (1.995)² = ?

Correct Answer: C [0.04]

Explanation:

(a + b)(a − b) = 4 × 0.01 = 0.04.

➤ Full notes, shortcuts and every answer explained – SSC CGL 2026 Quantitative Aptitude book (₹149): www.shanmugamiasacademy.in/study-materials/ssc-cgl-quantitative-aptitude

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