SSC CGL Science – Motion, Force & Laws of Motion – Level 2 · Exam Level · Tier I Sprint

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SSC CGL Science – Motion, Force & Laws of Motion – Level 2 · Exam Level · Tier I Sprint – 15 questions, subject: General Science. Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.

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1.  
A car starts from rest and accelerates uniformly at 3 m/s² for 8 s. The distance covered is:

Correct Answer: A [96 m]

Explanation:

Answer: 96 m. s = ½at² = ½ × 3 × 64 = 96 m.

2.  
A cyclist goes to a village at 30 km/h and returns along the same road at 20 km/h. The average speed for the whole journey is:

Correct Answer: C [24 km/h]

Explanation:

Equal distances: 2 × 30 × 20/(30 + 20) = 24 km/h.

3.  
A bus moving at 25 m/s is stopped with a uniform retardation of 5 m/s². The distance it moves before stopping is:

Correct Answer: B [62.5 m]

Explanation:

s = u²/(2a) = 625/10 = 62.5 m.

4.  
A ball is dropped from a height of 125 m. How long does it take to reach the ground? (g = 10 m/s²)

Correct Answer: D [5 s]

Explanation:

h = ½gt² → 125 = 5t² → t = 5 s.

5.  
A 5 kg gun fires a 25 g bullet with a speed of 300 m/s. The recoil speed of the gun is:

Correct Answer: D [1.5 m/s]

Explanation:

m_b v_b = m_g v_g → 0.025 × 300 = 5 × v → v = 1.5 m/s.

6.  
Match the followingMatch the event with the idea that explains it:
P. Passengers fall backward when a bus starts Q. A swimmer pushes water backward R. Airbags in cars S. Mud flies off a spinning tyre
1. Third law 2. Inertia of direction 3. Inertia of rest 4. Impulse – longer time, smaller force

Correct Answer: C [P-3, Q-1, R-4, S-2]

Explanation:

Bus start – inertia of rest; swimmer – third law; airbag – impulse; mud – inertia of direction (tangent).

7.  
Diagram-basedThe v–t graph of a body is shown. The distance covered in 10 s is:

Correct Answer: A [75 m]

Explanation:

Area = triangle ½ × 5 × 10 + rectangle 5 × 10 = 25 + 50 = 75 m.

8.  
What force is needed to give a 1200 kg car an acceleration of 2.5 m/s²?

Correct Answer: B [3000 N]

Explanation:

Answer: 3000 N. F = ma = 1200 × 2.5 = 3000 N.

9.  
Assertion–ReasonAssertion (A): A fielder moves his hands backward while catching a fast ball.
Reason (R): For the same change in momentum, increasing the time of contact reduces the force.

Correct Answer: A [Both A and R are true and R explains A]

Explanation:

F = Δp/Δt – a longer Δt gives a smaller force on the hands.

10.  
Two-quantity comparison
Quantity I: momentum of a 2 kg ball moving at 5 m/s
Quantity II: momentum of a 0.5 kg ball moving at 20 m/s

Correct Answer: C [Quantity I = Quantity II]

Explanation:

Answer: Quantity I = Quantity II. Both are 10 kg m/s.

11.  
Arrange in orderArrange in decreasing order of magnitude (same surfaces, same normal force): rolling friction, static (limiting) friction, sliding friction

Correct Answer: C [Static > Sliding > Rolling]

Explanation:

Limiting static friction is the largest, then sliding, and rolling friction is the least.

12.  
Odd one outWhich one is NOT an example of inertia of motion?

Correct Answer: D [Dust falls off a carpet when it is beaten]

Explanation:

The carpet case is inertia of rest; the others show a moving body trying to keep moving.

13.  
A force of 200 N acts on a ball for 0.05 s. The impulse given to the ball is:

Correct Answer: B [10 N s]

Explanation:

Impulse = F × t = 200 × 0.05 = 10 N s.

14.  
True/false countA stone is whirled in a horizontal circle at constant speed. How many of these are true?
I. Its speed is constant.
II. Its velocity is constant.
III. Its acceleration is directed towards the centre.
IV. If the string breaks, the stone flies off along the radius.

Correct Answer: C [2]

Explanation:

I and III are true. Velocity changes (direction), and the stone leaves along the tangent.

15.  
An s–t graph that is a straight line parallel to the time axis shows a body that is:

Correct Answer: D [at rest]

Explanation:

Position does not change with time → slope (velocity) = 0.

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