SSC CGL Science – Heat & Thermodynamics – Level 3 · Challenge

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SSC CGL Science – Heat & Thermodynamics – Level 3 · Challenge – 8 questions, subject: General Science. Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.

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1.  
At what temperature will the Fahrenheit reading be three times the Celsius reading?

Correct Answer: D [about 26.7 °C]

Explanation:

F = 3C → 3C = 1.8C + 32 → C = 32/1.2 ≈ 26.7 °C (= 80 °F).

2.  
How much heat (in calories) is needed to turn 5 g of ice at 0 °C into water at 50 °C? (L = 80 cal/g, c = 1 cal/g °C)

Correct Answer: C [650 cal]

Explanation:

5 × 80 + 5 × 50 = 400 + 250 = 650 cal.

3.  
A temperature rises by 45 °F. The rise on the Celsius scale is:

Correct Answer: B [25 °C]

Explanation:

Difference: ΔC = ΔF × 5/9 = 25 (no 32 for differences).

4.  
Spot My Mistake“Water at 0 °C is denser than water at 4 °C, so the bottom of a frozen lake is at 0 °C.” The correct statement is:

Correct Answer: C [Water is densest at 4 °C, so the bottom water stays near 4 °C]

Explanation:

Anomalous expansion: 4 °C water sinks to the floor.

5.  
Two kilograms of copper (c = 390 J/kg °C) at 100 °C is dropped into 1 kg of water (c = 4200 J/kg °C) at 20 °C. Ignoring losses, the final temperature is closest to:

Correct Answer: D [about 33 °C]

Explanation:

780(100 − T) = 4200(T − 20) → T = (78000 + 84000)/4980 ≈ 32.5 °C.

6.  
Which mode of heat transfer is NOT possible in a vacuum?

Correct Answer: A [conduction and convection]

Explanation:

Both need a material medium; radiation needs none.

7.  
A thermometer in a beaker of melting ice is heated gently. Until all the ice melts, the reading:

Correct Answer: C [stays at 0 °C]

Explanation:

The heat goes into latent heat of fusion.

8.  
Reverse questionThe answer is “the first law of thermodynamics”. Which statement is it?

Correct Answer: A [Heat supplied = increase in internal energy + work done]

Explanation:

Q = ΔU + W is the energy-conservation law.

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