SSC CGL Science – Periodic Table & Chemical Bonding – Tier II Level · Marathon
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O: (6 − 2) ÷ 2 = 2 lone pairs; N: (5 − 3) ÷ 2 = 1.
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SSC CGL Science – Periodic Table & Chemical Bonding – Tier II Level · Marathon – 10 questions, subject: General Science. Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.
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1.
The shape of the ammonia (NH₃) molecule is:
Correct Answer: C [pyramidal]
Explanation:
3 bond pairs + 1 lone pair on N → pyramidal.
2.
The H–C–H bond angle in methane is about:
Correct Answer: C [109.5°]
Explanation:
Four bond pairs, no lone pair → tetrahedral 109.5°.
3.
The hybridisation of carbon in carbon dioxide (O=C=O) is:
Correct Answer: A [sp]
Explanation:
Two electron regions → linear → sp.
4.
The number of σ and π bonds in a nitrogen molecule (N≡N) is:
Correct Answer: D [1 σ and 2 π]
Explanation:
Answer: 1 σ and 2 π. A triple bond = 1 σ + 2 π.
5.
Which molecule has the smallest bond angle?
Correct Answer: B [H₂O]
Explanation:
H₂O ≈ 104.5° (two lone pairs) < NH₃ ≈ 107° < CH₄ 109.5° < BF₃ 120°.
6.
The bond order in the oxygen molecule (O=O) is:
Correct Answer: A [2]
Explanation:
Answer: 2. A double bond → bond order 2.
7.
Assertion–Reason
A: The H–O–H bond angle in water is less than 109.5°.
R: Lone pairs repel bonding pairs more strongly than bonding pairs repel each other.
A: The H–O–H bond angle in water is less than 109.5°.
R: Lone pairs repel bonding pairs more strongly than bonding pairs repel each other.
Correct Answer: D [Both A and R are true and R explains A]
Explanation:
Two lone pairs on O squeeze the angle to about 104.5°.
8.
The correct order of bond strength is:
Correct Answer: C [N≡N > O=O > F–F]
Explanation:
Higher bond order → stronger bond: triple > double > single.
9.
The number of σ and π bonds in ethyne, H–C≡C–H, is:
Correct Answer: B [3 σ and 2 π]
Explanation:
Two C–H (2 σ) + C≡C (1 σ + 2 π) → 3 σ, 2 π.
10.
Two-quantity comparison
Quantity I: lone pairs on oxygen in H₂O
Quantity II: lone pairs on nitrogen in NH₃
Quantity I: lone pairs on oxygen in H₂O
Quantity II: lone pairs on nitrogen in NH₃
Correct Answer: B [Quantity I > Quantity II]
Explanation:
O: (6 − 2) ÷ 2 = 2 lone pairs; N: (5 − 3) ÷ 2 = 1.
➤ Full notes, shortcuts and every answer explained – SSC CGL 2026 General Science book (₹149): www.shanmugamiasacademy.in/study-materials/ssc-cgl-general-science
📘 SSC CGL 2026 – General Science (Tier I + Tier II)
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