SSC CGL Statistics – Measures of Central Tendency & Partition Values – Level 3 · Challenge
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Both move with change of origin and scale: 3 × 40 − 5 = 115, 3 × 38 − 5 = 109.
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SSC CGL Statistics – Measures of Central Tendency & Partition Values – Level 3 · Challenge – 8 questions, subject: Statistics (Tier II Paper II). Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.
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1.
Classes 0–10, 10–20, 20–30, 30–40, 40–50 have frequencies 3, x, 10, 7, 2. The mean is 24. Find x.
Correct Answer: D [8]
Explanation:
Σfx = 600 + 15x, N = 22 + x; 600 + 15x = 24(22 + x) → 9x = 72 → x = 8.
2.
Classes 0–10, 10–20, 20–30, 30–40, 40–50 have frequencies 4, 10, x, 12, 6. The mode is 26 and 20–30 is the modal class. Find x.
Correct Answer: A [16]
Explanation:
26 = 20 + (x − 10)/(2x − 22) × 10 → 0.6(2x − 22) = x − 10 → x = 16.
3.
The arithmetic mean of two positive numbers is 10 and their geometric mean is 8. What is their harmonic mean?
Correct Answer: C [6.4]
Explanation:
H = G²/A = 64/10 = 6.4 (the numbers are 16 and 4).
4.
A cyclist rides 60 km at 30 km/h and then 90 km at 45 km/h. What is the average speed for the whole journey?
Correct Answer: A [37.5 km/h]
Explanation:
Weighted HM: 150 km ÷ (2 h + 2 h) = 37.5 km/h.
5.
Diagram-basedThe less-than ogive of the marks of 80 students is shown.
What is the lower quartile Q₁?
What is the lower quartile Q₁?
Correct Answer: B [30]
Explanation:
N/4 = 20 and the ogive passes through (30, 20) → Q₁ = 30.
6.
True/False countHow many of the following statements are true?
(i) The mode can be located from a histogram.
(ii) The median can be located from an ogive.
(iii) The geometric mean can be found when one value is zero.
(iv) The harmonic mean gives the largest weight to the smallest values.
(i) The mode can be located from a histogram.
(ii) The median can be located from an ogive.
(iii) The geometric mean can be found when one value is zero.
(iv) The harmonic mean gives the largest weight to the smallest values.
Correct Answer: D [Three]
Explanation:
(i), (ii), (iv) are true; with a zero value the GM is zero and useless.
7.
Using the (n + 1) rule, find the third decile of 5, 8, 11, 12, 15, 18, 20, 22, 25, 27, 30, 34, 38, 41.
Correct Answer: B [13.5]
Explanation:
Position 3 × 15/10 = 4.5 → 12 + 0.5 × (15 − 12) = 13.5.
8.
For a variable x, the mean is 40 and the median is 38. If y = 3x − 5, what are the mean and the median of y?
Correct Answer: D [Mean 115, median 109]
Explanation:
Both move with change of origin and scale: 3 × 40 − 5 = 115, 3 × 38 − 5 = 109.
➤ Full notes, shortcuts and every answer explained – SSC CGL 2026 Statistics (Tier II Paper II) book (₹149): www.shanmugamiasacademy.in/study-materials/ssc-cgl-statistics
📘 SSC CGL 2026 – Statistics (Tier II Paper II)
Here you get the answer with a one-line explanation. 657 original questions with worked answers · notes, formulas, figures and statistical tables (z, t, χ², F) · practice sets + 3 mock tests
Get the book – ₹149 More quizzes
› SSC CGL Statistics – Mock Test M3 – Mixed Paper II Set (All 12 Chapters)
› SSC CGL Statistics – Mock Test M2 – Probability, Sampling, Inference & ANOVA (Chapters 6–10)
› SSC CGL Statistics – Mock Test M1 – Descriptive Statistics (Chapters 1–5)
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› SSC CGL Statistics – Index Numbers – Level 3 · Challenge
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