SSC CGL Statistics – Moments, Skewness & Kurtosis – Level 2 · Exam Level · Paper II Sprint
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Answer: 1. β₁ = μ₃²/μ₂³ = 64/64 = 1.
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SSC CGL Statistics – Moments, Skewness & Kurtosis – Level 2 · Exam Level · Paper II Sprint – 15 questions, subject: Statistics (Tier II Paper II). Every question has the correct answer with a one-line explanation; tap "Show Answer". Free practice for TNPSC, UPSC, SSC, Bank and RRB exams – Shanmugam IAS Academy, Coimbatore.
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1.
About A = 10, the first two raw moments of a distribution are 2 and 20. What is the variance?
Correct Answer: C [16]
Explanation:
μ₂ = μ′₂ − μ′₁² = 20 − 4 = 16.
2.
About A = 10, the first three raw moments are 2, 20 and 40. What is μ₃?
Correct Answer: B [−64]
Explanation:
μ₃ = 40 − 3(20)(2) + 2(8) = 40 − 120 + 16 = −64.
3.
The mean of a distribution is 30 and the first three raw moments about A = 30 are therefore:
Correct Answer: A [0, μ₂ and μ₃]
Explanation:
When A = mean, μ′₁ = 0 and raw moments equal central moments.
4.
μ₂ = 9 and μ₄ = 230. Which statement about the distribution is correct?
Correct Answer: D [It is platykurtic]
Explanation:
3μ₂² = 243 > 230 → β₂ = 230/81 ≈ 2.84 < 3 → platykurtic.
5.
Mean = 60, median = 63, SD = 15. Karl Pearson's (median form) coefficient of skewness is:
Correct Answer: C [−0.6]
Explanation:
Answer: −0.6. 3(60 − 63)/15 = −9/15 = −0.6.
6.
Q₁ = 24, median = 30, Q₃ = 33. Bowley's coefficient of skewness is:
Correct Answer: A [−0.33]
Explanation:
(33 + 24 − 60)/(33 − 24) = −3/9 = −1/3.
7.
The mean is 45, Karl Pearson's coefficient of skewness is −0.4 and the SD is 5. What is the mode?
Correct Answer: D [47]
Explanation:
Mode = Mean − Sk × σ = 45 + 2 = 47.
8.
For a variable x, μ₃ = 12. If y = 5 − 2x, what is μ₃ of y?
Correct Answer: B [-96]
Explanation:
Answer: -96. μ₃(y) = (−2)³ × 12 = −96.
9.
Two-quantity comparisonGiven that x has β₂ = 2.6 and y = 4x + 7:
Quantity I: β₂ of x
Quantity II: β₂ of y
Quantity I: β₂ of x
Quantity II: β₂ of y
Correct Answer: C [Quantity I = Quantity II]
Explanation:
β₂ is a pure number, unchanged by change of origin and scale.
10.
Assertion–Reason
A: In a negatively skewed distribution the mean is less than the mode.
R: The mean is pulled towards the longer tail of the distribution.
A: In a negatively skewed distribution the mean is less than the mode.
R: The mean is pulled towards the longer tail of the distribution.
Correct Answer: A [Both A and R are true and R explains A]
Explanation:
Negative skew has its long tail on the left; the mean moves left, below the mode.
11.
Odd one outwhich of these is NOT a measure of skewness?
Correct Answer: D [β₂]
Explanation:
Answer: β₂. β₂ measures kurtosis.
12.
Fill in the blankSheppard's correction for grouping is NOT applied to the ______ moment.
Correct Answer: B [third central]
Explanation:
μ₃ needs no correction; μ₂ and μ₄ are corrected.
13.
A grouped distribution with class width 12 has μ₂ = 40. What is its μ₂ after Sheppard's correction?
Correct Answer: C [28]
Explanation:
Answer: 28. 40 − 12²/12 = 40 − 12 = 28.
14.
P₁₀ = 15, P₅₀ = 35, P₉₀ = 65. Kelly's coefficient of skewness is:
Correct Answer: C [0.2]
Explanation:
(65 + 15 − 70)/(65 − 15) = 10/50 = 0.2.
15.
Spot My Mistake“μ₂ = 4, μ₃ = 8, so β₁ = μ₃/μ₂ = 2.” What is the correct β₁?
Correct Answer: D [1]
Explanation:
Answer: 1. β₁ = μ₃²/μ₂³ = 64/64 = 1.
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📘 SSC CGL 2026 – Statistics (Tier II Paper II)
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