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1. How many days will B alone take to finish the job?
Directions (Q 36–39): A municipal office in Tiruppur gives a record-scanning job to three clerks. A alone can finish the job in 36 days. B is 20% more efficient than A, and C is 20% less efficient than A.
Correct Answer: D [30 days]
Explanation:
A : B : C = 5 : 6 : 4; work = 5 × 36 = 180 units → B = 180 ÷ 6 = 30 days.
2.
(Use the directions above – Time & Work, Pipes & Cisterns, Q 36–39)
All three start together. After 6 days B is moved to another job, and A and C finish the rest. In how many days in all is the job finished?
All three start together. After 6 days B is moved to another job, and A and C finish the rest. In how many days in all is the job finished?
Correct Answer: E [16 days]
Explanation:
6 days × 15 = 90 units; remaining 90 ÷ (5 + 4) = 10 days → 16 days.
3.
(Use the directions above – Time & Work, Pipes & Cisterns, Q 36–39)
If all three work together for the whole job and are paid ₹ 30,000, C's share is:
If all three work together for the whole job and are paid ₹ 30,000, C's share is:
Correct Answer: B [₹ 8,000]
Explanation:
Share in efficiency ratio 5 : 6 : 4 → C gets 4/15 × 30,000 = ₹ 8,000.
4.
(Use the directions above – Time & Work, Pipes & Cisterns, Q 36–39)
B works alone for some days; then A and C together finish the remaining job in 8 days. For how many days did B work?
B works alone for some days; then A and C together finish the remaining job in 8 days. For how many days did B work?
Correct Answer: A [18 days]
Explanation:
A + C = 9 units/day × 8 = 72 units; B did 180 − 72 = 108 units → 108 ÷ 6 = 18 days.
5.
Quantity I: Hours to fill an empty tank with inlets P (12 h) and Q (18 h) open and a leak that empties the full tank in 36 h.
Quantity II: Days 18 women need for a job that 12 women finish in 12 days.
Quantity II: Days 18 women need for a job that 12 women finish in 12 days.
Correct Answer: A [Quantity I > Quantity II]
Explanation:
I: LCM 36: 3 + 2 − 1 = 4 units/h → 9 h.
6.
A and B together finish a job in 20 days, and one of them takes 30 days more than the other.
Quantity I: Days A alone takes.
Quantity II: 30
Quantity I: Days A alone takes.
Quantity II: 30
Correct Answer: C [Quantity I ≥ Quantity II]
Explanation:
Faster one 30 days, slower 60 days (30 × 60/90 = 20).
7.
In how many hours can outlet C alone empty the full tank?
I. Inlets A and B alone fill the tank in 10 h and 15 h respectively.
II. With A, B and C all open, the empty tank fills in 12 h.
I. Inlets A and B alone fill the tank in 10 h and 15 h respectively.
II. With A, B and C all open, the empty tank fills in 12 h.
Correct Answer: D [Both statements together are needed]
Explanation:
Need both: 1/10 + 1/15 − 1/C = 1/12 → 1/C = 1/6 − 1/12 = 1/12 → C = 12 h.
8.
In how many days can A alone finish the job?
I. A and B together finish it in 12 days, and B is 25% less efficient than A.
II. B alone takes 28 days.
I. A and B together finish it in 12 days, and B is 25% less efficient than A.
II. B alone takes 28 days.
Correct Answer: A [Statement I alone is sufficient]
Explanation:
I: A : B = 4 : 3; work = 7 × 12 = 84 → A = 21 days.
9.
In how many days will 10 men finish the job?
I. 6 men and 4 women finish it in 12 days.
II. 5 men finish it in 24 days.
I. 6 men and 4 women finish it in 12 days.
II. 5 men finish it in 24 days.
Correct Answer: B [Statement II alone is sufficient]
Explanation:
II: 5 × 24 = 120 man-days → 10 men need 12 days.
10.
P is twice as efficient as Q, and Q is 40% more efficient than R. P, Q and R together finish a job in 10 days. How many days will R alone take?
Correct Answer: E [52 days]
Explanation:
R : Q : P = 5 : 7 : 14 → 26 units/day × 10 = 260 → R = 260 ÷ 5 = 52 days.
11.
Pipes A and B can fill a tank in 10 hours and 15 hours. They are opened alternately for one hour each, A first. In how many hours is the empty tank full?
Correct Answer: D [12 hours]
Explanation:
LCM 30: A 3, B 2 → 5 per 2 h; 5 cycles = 25 in 10 h; hour 11 (A) → 28, hour 12 (B) → 30.
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